[프로그래머스 | 자바스크립트] 숨어있는 숫자의 덧셈(2)

솔루션

const solution = (my_string) => {
  const nums = my_string.match(/[0-9]+/g);

  const answer = nums ? nums.map((num) => +num).reduce((a, c) => a + c, 0) : 0;
  console.log(answer);

  return answer;
};

솔루션

function solution(my_string) {
  const answer = my_string.split(/\D+/).reduce((acc, cur) => acc + Number(cur), 0);
  console.log(answer);
  
  return answer;
}

솔루션

function solution(n) {
    let answer = ""
    for(let i = 0 ; i<n.length; i++){
        if(Number.isInteger(+n[i])){
            answer += n[i]
        }else{
            answer += " "
        }
    }
    console.log(answer);
    
    return answer.split(" ").reduce((acc,cur)=> acc += +cur,0)
}